I forgot to mention that when you put lines into
slope-intercept form (y = mx + b), it is easy to
recognize parallel lines: they have the same
slope (m), but different y-intercepts (b).
I also mentioned slopes as being a 'rise' over
a 'run'. If the slope is an integer value such
as 5, remember that 5 is the same as 5/1. In
this case, you would count up 5 steps, and then
go 1 to the right to find a point on the line
relative to the y-intercept. If the value is
negative, for example -2/3, you would count
*down* 2 steps, and then count 3 to the right.
Remember: To graph a line using slope-intercept
form, you need to plot two points and draw the
line through them. Your first point is always
the y-intercept (0,b) and your second point is
obtained by counting out the slope from the first
point.
If your teacher described a different way of
plotting points, you should stick with his/her
approach. This is just the approach that I
have always used.
Let me know if you need anything else.
lin-chan12 Community Member 
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